Tuple<T1,T2,T3,T4,T5,T6,T7>.Item3 Egenskap

public:
 property T3 Item3 { T3 get(); };

public T3 Item3 { get; }

member this.Item3 : 'T3

Public ReadOnly Property Item3 As T3

Egenskapsvärde

Värdet för det aktuella Tuple<T1,T2,T3,T4,T5,T6,T7> objektets tredje komponent.

Exempel

I följande exempel definieras en matris med Tuple<T1,T2,T3,T4,T5,T6,T7> objekt vars komponenter innehåller befolkningsdata för tre amerikanska städer (New York, Chicago och Los Angeles) från 1950 till 2000. Den visar sedan en tabell som visar data. Om du vill visa populationen 1960 hämtar den värdet Item3 för egenskapen för varje Tuple<T1,T2,T3,T4,T5,T6,T7> objekt.

using System;
using System.Text.RegularExpressions;

public class Class1
{
   public static void Main()
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", new String('-',(66-header.Length)/2) + header + 
                                new String('-', (66-header.Length)/2));
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}\n", 
                        "1950", "1960", "1970", "1980", "1990", "2000");         

      foreach (var city in cities)                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7);
   }
}
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

open System

// Create tuples containing population data for New York, Chicago, 
// and Los Angeles, 1960-2000.
let cities =
    [| Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278)
       Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820)
       Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) |]

// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(66 - header.Length) / 2) + header + String('-', (66 - header.Length) / 2),66}""" 
printfn "%24s%11s%11s%11s%11s%11s\n" "1950" "1960" "1970" "1980" "1990" "2000"         

for city in cities do
    printfn $"{city.Item1,-12} {city.Item2,11:N0}{city.Item3,11:N0}{city.Item4,11:N0}{city.Item5,11:N0}{city.Item6,11:N0}{city.Item7,11:N0}"
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Module Example
   Public Sub Main()
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 
                          7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 
                          2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", New String("-"c,(66-header.Length)\2) + header + _
                                New String("-"c, (66-header.Length)\2))
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}", 
                        "1950", "1960", "1970", "1980", "1990", "2000")                  
      Console.WriteLine()
      For Each city In cities                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7)
      Next
   End Sub
End Module
' The example displays the following output:
'    City          --------------------------Population in--------------------------
'                        1950       1960       1970       1980       1990       2000
'    
'    New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
'    Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
'    Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Kommentarer

Du kan dynamiskt fastställa komponenttypen Item3 på något av två sätt:

• Genom att anropa GetType metoden för det värde som returneras av Item3 egenskapen.

• Genom att hämta objektet Type som representerar Tuple<T1,T2,T3,T4,T5,T6,T7> objektet och hämta det tredje elementet från matrisen som returneras av dess Type.GetGenericArguments metod.